Nalorphene $(C_{19} H_{21} {N O}_{3})$ similar to morphine, is used to combat withdrawal symptoms in narcotic users. Does of nalorphene generally given is 1.5 mg. Calculate the mass of $15 \times 10^{- 3}$ m aqueous solution required for the above dose.

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Solution

$w_{B} = 1.5 \times 10^{- 3} g$

$M_{B} = 19 \times 12 + 21 \times 1 + 14 + 3 \times 16 = 311$

We know, $m = \frac{w_{B} / M_{B}}{w_{A}} \times 1000$

$1.5 \times 10^{- 3} = \frac{1.5 \times 10^{- 3} / 311}{w_{A}} \times 1000$

$w_{A} = \frac{1.5 \times 10^{- 3}}{311 \times 1.5 \times 10^{- 3}} \times 1000$

$∴ w_{A} = \frac{1000}{311} = 3.215 g$
$w = w_{A} + w_{B} = 3.2154 + 0.0015 \approx 3.217 g$

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Nalorphene (C19H21NO3) similar to morphine, is used to combat withdrawal symptoms in narcotic users. Does of nalorphene generally given is 1.5 mg. Calculate the mass of 15×10−3m aqueous solution required for the above dose.

wB=1.5×10−3gMB=19×12+21×1+14+3×16=311We know, m=wB/MBwA×10001.5×10−3=1.5×10−3/311wA×1000wA=1.5×10−3311×1.5×10−3×1000∴wA=1000311=3.215 gw=wA+wB=3.2154+0.0015≈3.217g

Nalorphene $(C_{19} H_{21} {N O}_{3})$ similar to morphine, is used to combat withdrawal symptoms in narcotic users. Does of nalorphene generally given is 1.5 mg. Calculate the mass of $15 \times 10^{- 3}$ m aqueous solution required for the above dose.