Name the oxide of sulphur which reacts with water to give sulphuric acid.

$S O_{2}$

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$S O_{3}$

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$S_{2} O$

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Solution

The correct option is B
$S O_{3}$

Sulphur trioxide reacts with water to give sulphuric acid.

$S O_{3} + H_{2} O \to H_{2} S O_{4}$

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Q. (a) Name the oxide of sulphur which reacts with water to give sulphuric acid.
(b) In the Contact Process, the direct reaction between the oxide of sulphur an water is avoided. In this process; what does the oxide of sulphur react with instead of water and what is the name of the product?
(c) Give the name and formula of the acidic salt which can give sodium ions and sulphate ions in solution.
[5 MARKS]

Name the oxide of sulphur which reacts with water to give sulphuric acid.
In the contact process, the direct reaction between oxide of sulphur and water is avoided. In this process, what does the oxide of sulphur react with instead of water, and what is the name of the product?

Q. Sulphur reacts with water directly to give sulphuric acid.

Q. Name the base formed when:
1. Sodium reacts with oxygen
2. Sodium oxide reacts with water
3. Copper oxide reacts with sulphuric acid
4. Sodium hydroxide reacts with (\H_2SO_4\)

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Name the oxide of sulphur which reacts with water to give sulphuric acid.

The correct option is B SO3 Sulphur trioxide reacts with water to give sulphuric acid. SO3+H2O→H2SO4

The correct option is B
$S O_{3}$

Sulphur trioxide reacts with water to give sulphuric acid.

$S O_{3} + H_{2} O \to H_{2} S O_{4}$