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Question
Nandini's house is \( \frac{9}{10} \) km from her school. She walked some distance and then took a bus for \( \frac{1}{2} \) km to reach the school. How far did she walk?
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Solution
As per the question
Total distance between school and Nandini's house = \( \frac{9}{10} \) km
Distance covered by bus = \( \frac{1}{2} \) km
Total distance between the school and Nandini's house = Distance covered by walking + Distance covered by bus
\(\Rightarrow\) Distance covered by walking = Total distance between the school and Nandini's house - Distance covered by bus
On substituting the values we get:
Distance covered by walking = \( \frac{9}{10}-\frac{1}{2}=\frac{9\times1-1\times5}{10} \) [ \( \because \) L.C.M. of 10 and 2 is 10 ]
= \(\frac{9-5}{10 }=\frac{4}{10}=\frac{2}{5} \) km
Therefore, she walked \( \frac{2}{5} \) km.
As per the question
Total distance between school and Nandini's house = \( \frac{9}{10} \) km
Distance covered by bus = \( \frac{1}{2} \) km
Total distance between the school and Nandini's house = Distance covered by walking + Distance covered by bus
\(\Rightarrow\) Distance covered by walking = Total distance between the school and Nandini's house - Distance covered by bus
On substituting the values we get:
Distance covered by walking = \( \frac{9}{10}-\frac{1}{2}=\frac{9\times1-1\times5}{10} \) [ \( \because \) L.C.M. of 10 and 2 is 10 ]
= \(\frac{9-5}{10 }=\frac{4}{10}=\frac{2}{5} \) km
Therefore, she walked \( \frac{2}{5} \) km.
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