NaNO2-A- B - N2 A-AgNO3- White ppt soluble in C A CHence- A is -

The correct option is B NH _ 4 Cl Sodium nitrite #160; reacts with ammonium chloride forms ammonium nitrate which on heating produces nitrogen. NaN ...

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Byju's Answer

Standard X

Chemistry

Reducing Properties of Ammonia

NaNO2+A⟶ B ⟶ ...

Question

$N a N O_{2} + A ⟶ B ⟶ N_{2}$

$A + A g N O_{3} ⟶$ White ppt soluble in C

$A N a O H, Δ - ---- \to C$
Hence, $A$ is :

N a C l

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{N H}_{4} C l

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{N H}_{4} {N O}_{2}

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{N H}_{4} {N O}_{3}

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Solution

The correct option is B ${N H}_{4} C l$
Sodium nitrite reacts with ammonium chloride forms ammonium nitrate which on heating produces nitrogen.
$N a N O_{2} + N H_{4} C l \to N a C l + N H_{4} N O_{2} h e a t - - \to H_{2} O + N_{2} ↑$ ..
Ammonium chloride reacts with silver nitrate to produce white ppt of silver chloride which is soluble in ammonia (compound C).
$N H_{4} C l + A g N O_{3} \to N H_{4} N O_{3} + A g C l ↑$

$A g C l + 2 N H_{3} \to A g (N H_{3})_{2} C l (s o l u b l e)$ .

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Similar questions

A colourless mixture of two substances (A) and (B) (excess) is soluble in

H_{2} O

, separately. (A) turns blue litmus red and (B) turns red litmus blue. (A) gives white ppt. with (B), which dissolves in excess of (B) forming (C). (A) when placed in moist air gives fumes and can form a dimer. (A) gives white ppt. with

{N H}_{4} C l

and

{N H}_{4} O H

soluble in (B). (A) also gives white precipitate with

{A g N O}_{3}

soluble in

{N H}_{4} O H

Thus, colourless mixture contains ___________.

A colourless mixture of two substances, (A) and (B) (excess) is soluble in

H_{2} O

{N H}_{4} C l

and

{N H}_{4} O H

soluble in (B). (A) also gives white precipitate with

{A g N O}_{3}

soluble in

{N H}_{4} O H

Thus, dimer formed has _______ bonding .

Q. A colourless mixture of two substances (A) and (B) (excess) is soluble in

H_{2} O

{N H}_{4} C l

and

{N H}_{4} O H

soluble in (B). (A) also gives white precipitate with

{A g N O}_{3}

soluble in

{N H}_{4} O H

Thus, A turns blue litmus red. It is due to acidic solution because of ________.

Q. The species having

s p^{3}

hybridisation of atomic orbitals of nitrogen is/are

N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}, N F_{3}

are

Q. If the identifications given below are true enter 1, else enter 0.
(A) :

{N H}_{4} {N O}_{2}

(B) :

{N H}_{3}

{N a N O}_{2}

(D) :

N_{2}

(E) :

A l N

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NaNO2+A⟶B⟶N2A+AgNO3⟶ White ppt soluble in CANaOH,Δ−−−−−→CHence, A is :

$N a N O_{2} + A ⟶ B ⟶ N_{2}$

$A + A g N O_{3} ⟶$ White ppt soluble in C

$A N a O H, Δ - ---- \to C$
Hence, $A$ is :