The correct option is A PH_3 + NaH_2PO_2 P_4 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160;+ 3NaOH + 3H_2O ...

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Phosphine

NaOH+ P4 + H2...

Question

$N a O H + P_{4} + H_{2} O \to$

P H_{3} + N a H_{2} P O_{2}

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P H_{3} + N a_{2} P O_{4}

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P H_{3} + N a_{2} H P O_{2}

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H_{3} P O_{4} + N a O

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Solution

The correct option is A $P H_{3} + N a H_{2} P O_{2}$
$P_{4} + 3 N a O H + 3 H_{2} O \to$
white phosphorus
$P H_{3} + 3 N a H_{2} P O_{2}$
Phosphine Sodium hypophosphate

Suggest Corrections

Similar questions

P_{4} + N a O H \to P H_{3} + N a H_{2} P O_{2}

N a H_{2} P O_{2}

P H_{3}

B + N a O H \to 2 N a_{3} B O_{3} + H_{2}

P_{4} + N a O H + H_{2} O \to N a H_{2} P O_{2} + P H_{3}

S + N a O H \to N a_{2} S_{2} O_{3} + N a_{2} S + H_{2} O

P + N a O H + H_{2} O \to N a H_{2} P O_{2} + P H_{3}

P_{4}

P_{4} + N a O H \to N a H_{2} P O_{2} + P H_{3}

P + N a O H \to P H_{3} + N a H_{2} P O_{2}

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