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Elastic Potential Energy

Natural lengt...

Question

Natural length of the spring is $40$ cm and its spring constant is $4000 N m^{- 1}$ . A mass of $20$ kg is hung from it. The extension produced in the spring is (Given g = $9.8 m s^{- 2})$

A

4.9

cm

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B

0.49

cm

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C

9.4

cm

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D

0.94

cm

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Solution

The correct option is B $4.9$ cm
In equilibrium, $k x = m g$

$∴ x = \frac{m g}{k} = \frac{20 \times 9.8}{4000} = 0.049 m = 4.9 c m$

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