Negative inductive effect is shown by:

- C H_{3}

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- C H_{2} C H_{3}

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- N H_{3}^{+}

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(C H_{3})_{2} C H -

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Solution

The correct option is C $- N H_{3}^{+}$
Among the given, $- C H_{3}, - C H_{2} C H_{3}$ and $(C H_{3})_{2} C H -$ being electron releasing, increase the electron density, so exhibit positive inductive effect while $- N H_{3}^{+}$ exhibits negative inductive effect.

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Similar questions

Q. Arrangement of

(C H_{3})_{3} C -, (C H_{3})_{2} C H -, C H_{3} - C H_{2} -

when attached to benzyl or an unsaturated group in increasing order of inductive effect is:

Q. Assertion :The order of stability of carbanion are

(C_{6} H_{5})_{3} C^{-} > C_{6} H_{5} C H_{2}^{-} > a l l y l > C H_{3}^{-} > (C H_{3})_{2} C H^{-}

Reason: The stabiliby of carbanions is influenced by both resonance and inductive effects.

Q. The type of isomerism shown by the following set of compounds is:

{C H}_{3} C H_{2} {C H}_{2} {C H}_{2} {C H}_{3}, {C H}_{3} - {C H}_{3} | C H - {C H}_{2} C H_{3}, {C H}_{3} - {C H}_{3} | C_{3} - {C H}_{3}

The arrangement of $(C H_{3})_{3} C -, (C H_{3})_{2} C H -, C H_{3} C H_{2} -$ When attached to a benzene or an unsaturated group in increasing order of inductive effect is:

Q. Comp

(A) C_{4} H_{8} C l_{2}

in by hydrolyzed to compound

B

with formula

C_{4} H_{8} O

which gives oxime & negative Tollens test. The compound

B

is:

C H_{3} - C l | C | C l - C H_{2} C H_{3}

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Negative inductive effect is shown by:

The correct option is C −NH+3Among the given, −CH3,−CH2CH3 and (CH3)2CH− being electron releasing, increase the electron density, so exhibit positive inductive effect while −NH+3 exhibits negative inductive effect.

The correct option is C $- N H_{3}^{+}$
Among the given, $- C H_{3}, - C H_{2} C H_{3}$ and $(C H_{3})_{2} C H -$ being electron releasing, increase the electron density, so exhibit positive inductive effect while $- N H_{3}^{+}$ exhibits negative inductive effect.