Question

Neglecting the air resistance, the time of flight of a projectile is determined by ($U\to$ Initial velocity).

• A. $U_{vertical}$
• B. $U_{horizontal}$
• C. $U=U_{vertical}^2+U_{horizontal}^2$
• D. $U=U(U_{vertical}^2+U_{horizontal}^2{)}^{12}$

Answer 1

The correct option is A $U_{vertical}$

Distance verses time graph gives us velocity.

And we know Time of flight $T=u_0\frac{\sin \theta }{g}$

So if we neglect the angle of projectile and gravitation than time of flight T=$u_{vertical}$