Nernst equation is - E - Eo - RT-nF ln Q- If Q - Kc- then which one is not correct-

The correct option is A E = E^o According to equation, E = E^o RTnF ln #160;Q At equilibrium, E=0 E^o = RTnF ln K_c ∴ #160;K_c ...

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Nernst Equation

Nernst equati...

Question

Nernst equation is : $E = E^{o} - \frac{R T}{n F} l n Q$ . If $Q = K_{c}$ , then which one is not correct?

E = E^{o}

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\frac{R T}{n F} l n Q = E^{o}

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E = z e r o

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K_{c} = e^{\frac{n F E^{o}}{R T}}

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Solution

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Similar questions

E^{o}

\frac{1}{2} F_{2} + e^{-} ⟶ F^{-}

E^{o}

\frac{1}{2} C l_{2} + e^{-} ⟶ C l^{-}

E^{o}

\frac{1}{2} B r_{2} + e^{-} ⟶ B r^{-}

E^{o}

\frac{1}{2} I_{2} + e^{-} ⟶ I^{-}

E^{o}

{C u}^{+} + e^{-} ⟶ C u, E^{o} = x_{1}

{C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{o} = x_{2}

{C u}^{+} + e^{-} ⟶ {C u}^{+}, E^{o}

E^{o}

{[F e {(C N)}_{6}]}^{4 -} ⟶ {[F e {(C N)}_{6}]}^{3 +} + e^{-}, E^{o} = - 0.35 V

{F e}^{2 +} \to {F e}^{3 +} + e^{- 1}

{F e}^{2 +} \to {F e}^{3 +} + e^{- 1}; E^{o} = - 0.77 V

A + B ⇌ C + D; E^{o} = a v o l t; K_{c} = K_{1}

2 A + 2 B ⇌ 2 C + 2 D; E^{o} = b v o l t; K_{c} = K_{2}

\to

+ e^{-}

E^{o} = - 0.35 V

\to

+ e^{-}

E^{o} = - 0.77 V

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