Question

Neutron decay in free space is given as follows:
${}_e{n}^1{\to }_0{H}^1{+}_{-o}{e}^0+\left[\right]$
Then the parenthes is represents a

• A. Neutrion
• B. Photon
• C. Antineutrino
• D. Gravition

Answer 1

The correct option is C Antineutrino

${}_e{n}^1{\to }_0{H}^1{+}_{-1}{e}^0+\text{some particles}$

$\begin{array}{c}\text{The given decay is similar to}{\beta }^{-}\text{decay.}\\ \text{To maintain the momentum, angular momentum}\\ \text{spin moment. The particle released is antineutrino.}\end{array}$