You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation Number Method

NF3g+H2Og → H...

Question

$N F_{3} (g) + H_{2} O (g) \to H F (g) + N O (g) + N O_{2} (g)$
Balance the above given chemical reaction and find out the total number of moles of $N F_{3}$ that will react with 6 moles of $H_{2} O$ .

4 mole

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 moles

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 moles

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 moles

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 4 mole
The unbalanced chemical equation is,
$N F_{3} (g) + H_{2} O (g) \to H F (g) + N O (g) + N O_{2} (g)$
Balance $N$ atoms by adding 2 to $N F_{3}$ on LHS.
$2 N F_{3} (g) + H_{2} O (g) \to H F (g) + N O (g) + N O_{2} (g)$
Balance $F$ by adding 6 to $H F$ on RHS.
$2 N F_{3} (g) + H_{2} O (g) \to 6 H F (g) + N O (g) + N O_{2} (g)$
Balance $H$ by adding 3 to $H_{2} O$ on LHS.
$2 N F_{3} (g) + 3 H_{2} O (g) \to 6 H F (g) + N O (g) + N O_{2} (g)$
This is balanced chemical equation.
3 moles of water reacts with 2 moles of $N F_{3}$ .
6 moles of water will react with $2 \times 2 = 4$ moles of $N F_{3}$ .

Suggest Corrections

Similar questions

6

C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)

N H_{4} C l

N H_{3}

C l_{2}

N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

3.8

N O

0.924

C O_{2}

1.0 L

0.124

C O_{2}

K_{c}

N O_{(g)} + C O_{(2 (g)} ⇌ N O_{2 (g)} + C O_{(g)}

1

N O

1

O_{3}

10 L

50 %

N O

O_{3}

N O (g) + O_{3 (g)} ⇌ N O_{2 (g)} + O_{2 (g)}

Join BYJU'S Learning Program