$(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}$

The mass of $C r_{2} O_{3}$ formed by the decomposition of 63 gm of ammonium dichromate :

$[N = 14, H = 1, O = 16, C r = 52]$

38 g

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76 g

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19 g

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152 g

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Solution

The correct option is A 38 g
$(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}$

One mole of potassium dichromate gives one mole of nitrogen and chromium oxide.

Moles of potassium dichromate is $\frac{63}{252} = 0.25 m o l e s$

Therefore, moles of $C r_{2} O_{3}$ formed is 0.25 moles.

So, mass of $C r_{2} O_{3} = 0.25 \times 152$
$= 38 g$

Hence, option $A$ is correct.

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Similar questions

(NH₄)₂Cr₂O₇ $\overset{}{\to}$ N₂ + Cr₂O₃ + 4H₂O. What volume of nitrogen at STP, will be evolved when 63 g of ammonium dichromate is decomposed? (H = 1, N = 14, O = 16, Cr = 52)

(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}

Calculate the volume of nitrogen at STP, evolved when 63 g of ammonium dichromate is heated.

Q. Ammonium dichromate on heating decompose to form nitrogen and chromium ( lll) oxide and water what will be the loss in mass if 31.5 gram of Ammonium dichromate is heated at 100°C
(chromium=52,nitrogen=14,hydrogen=1,oxygen =16)
(NH4 )²Cr2O7 gives N2+Cr2O3+4H2O

(N H_{4})_{2} C r_{2} O_{7} h e a t \to N_{2} (g) + 4 H_{2} O (g) + C r_{2} O_{3}

The mass of grams of

C r_{2} O_{3}

formed during the reaction is________. [Atomic masses: H=1, Cr=52, N=14]

Q. The reaction

(N H_{4})_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O

, is an example of :

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(NH4)2Cr2O7→Cr2O3+4H2O+N2The mass of Cr2O3 formed by the decomposition of 63 gm of ammonium dichromate :[N=14,H=1,O=16,Cr=52]

The correct option is A 38 g(NH4)2Cr2O7→Cr2O3+4H2O+N2One mole of potassium dichromate gives one mole of nitrogen and chromium oxide.Moles of potassium dichromate is 63252=0.25 moles Therefore, moles of Cr2O3 formed is 0.25 moles.So, mass of Cr2O3=0.25×152 =38g Hence, option A is correct.

$(N H_{4})_{2} C r_{2} O_{7} \to C r_{2} O_{3} + 4 H_{2} O + N_{2}$

The mass of $C r_{2} O_{3}$ formed by the decomposition of 63 gm of ammonium dichromate :

$[N = 14, H = 1, O = 16, C r = 52]$