NH 4 HSs- NH 3 g- H 2 Sg- The equilibrium pressure at 25 -C is 0-66 atm- What is the Kp of the reaction-

The correct option is A 0.1089 NH _ 4 HS _( S ) #160; ⇌ NH _ 3( g ) #160; + H _ 2 S _( g ) #160; K _ P = PNH _ 3 . PH _ 2 S P=0.66atm ...

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Derivation of Kp and Kc

NH 4 HSs⇌ NH ...

Question

${N H}_{4} H S (s) ⇌ {N H}_{3} (g) + H_{2} S (g)$ . The equilibrium pressure at $25^{\circ} C$ is 0.66 atm. What is the Kp of the reaction?

0.1089

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0.4356

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0.66

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0.2178

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Solution

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