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VBT Tetrahedral vs Square Planar

[NiCN4]2⊖ and...

Question

$[N i (C N)_{4}]^{2 ⊖}$ and $[N i C l_{4}]^{2 ⊖}$ are dissimilar with respect to

A

magnetic moment

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B

Coordination number

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C

structure

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D

Both (a) and (c)

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Solution

The correct option is D Both (a) and (c)
$[N i (C N)_{4}]^{2 ⊖}$ is square planar and diamagnetic whereas $[N i C l_{4}]^{2 ⊖}$ is tetrahedral and paramagnetic

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Similar questions

[N i (C N)_{4}]^{2 ⊖}

[N i C l_{4}]^{2 ⊖}

are dissimilar with respect to

[N i (C O)_{4}], [N i (C N)_{4}]^{2 -}

[N i C l_{4}]^{2 -}

species, the hybridisation state of

N i

atoms are respectively:

Q. The hybridisation of

[N i C l_{4}]^{2 -}

[N i (C N)_{4}]^{2 -}

considering hybridization of the metal ion are respectively:

Q. The structure of

[N i C l_{4}]^{2 -}

[N i (C N)_{4}]^{2 -}

considering the hybridisation of the metal ion are respectively:

Among $[N i (C O)_{4}]$ , $[N i (C N)_{4}]^{- 2}$ and $[N i (C l)_{4}]^{- 2}$ :

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VBT Tetrahedral vs Square Planar

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