Question

Question 24

Nickel atom can lose two electrons to form $N{i}^{2+}$ ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons ?

Answer 1

${}_{28}Ni=1s^2,2s^2,2p^6,3s^2,3p^6,3d^8,4s^2$ ; Nickel will lose 2 electrons from 4s (outermost shell) to form $N{l}^{2+}$ ion.
Hence, ${}_{28}N{i}^{2+}=1s^2,2s^2,2p^6,3s^2,3p^6,3d^8,4s^0$