nitrogen and hydrogen combine in the ratio of 14:3 by mass to form NH3. what mass of ammonia is formed if 2.8g of nitrogen reacts with hydrogen

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Solution

N₂+ 3 H₂→ 2 NH₃
1 mol of N₂reacts to form 2 moles of NH₃.

Or 28 g of N₂react to form 34 g of NH₃.
Hence 2.8 g will form $\frac{34}{28} \times 2.8$ = 3.4 g.

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nitrogen and hydrogen combine in the ratio of 14:3 by mass to form NH3. what mass of ammonia is formed if 2.8g of nitrogen reacts with hydrogen

N2 + 3 H2 → 2 NH3 1 mol of N2 reacts to form 2 moles of NH3. Or 28 g of N2 react to form 34 g of NH3. Hence 2.8 g will form 3428×2.8 = 3.4 g.

N₂+ 3 H₂→ 2 NH₃
1 mol of N₂reacts to form 2 moles of NH₃.

Or 28 g of N₂react to form 34 g of NH₃.
Hence 2.8 g will form $\frac{34}{28} \times 2.8$ = 3.4 g.