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Byju's Answer

Standard XII

Chemistry

SHE

No/2 atoms of...

Question

No/2 atoms of $X_{(g)}$ are converted into $X_{(g)^{+}}^{+}$ by energy $E_{1}$ , No/2 atoms of $X_{g}$ are converted into $X_{(g)}^{-}$ by energy $E_{2}$ . Hence ionization potential and electron affinity of $X_{(g)}$ per atom are

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Solution

The correct option is A

$X_{(g)} \to X_{g}^{+} + e^{-}$
Energy required to ionise $\frac{N o}{2}$ atoms of $X_{g} = \frac{N o}{2} \times I . E = E_{1}$ (given)

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Similar questions

N_o/2 atoms of X(g) are converted into X⁺(g) by energy E₁. N_o/2 atoms of X(g) are converted into X^-(g) by energy E₂. Hence the ionisation potential and electron affinity of X(g) per atom are:

A. 2E₁/N_o., 2(E₂-E₁)/N_o

B. 2E₁/N_o.,. 2E₂/N_o

C. E₁-E₂/N_{o. ,.}2E₂/N_o

D. None is correct

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by energy

E_{1}

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{-} (g)

by energy

E_{2}

. Hence, ionisation potential and electron affinity of

X (g)

are:

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

\frac{N_{0}}{2}

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing

E_{1}

energy.

2 N_{0}

atoms of

X (g)

are converted into

X^{-} (g)

by releasing

E_{2}

energy. Calculate the ionisation enthalpy and electron gain enthalpy of

X (g)

per atom.

A_{0} / 2

atoms of

X (g)

are converted into

X^{+} (g)

by absorbing energy

E_{1}

A_{0} / 2

X^{+} (g)

are converted into

X^{-} (g)

with the release of energy,

E_{2}

. Hence the ionisation energy and the electron affinity of

X (g)

are repectively _____ and _______.

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No/2 atoms of X(g) are converted into X+(g)+ by energy E1, No/2 atoms of Xg are converted into X−(g) by energy E2. Hence ionization potential and electron affinity of X(g) per atom are

The correct option is A X(g)→X+g+e− Energy required to ionise No2 atoms of Xg=No2×I.E=E1(given)

No/2 atoms of $X_{(g)}$ are converted into $X_{(g)^{+}}^{+}$ by energy $E_{1}$ , No/2 atoms of $X_{g}$ are converted into $X_{(g)}^{-}$ by energy $E_{2}$ . Hence ionization potential and electron affinity of $X_{(g)}$ per atom are

The correct option is A

$X_{(g)} \to X_{g}^{+} + e^{-}$
Energy required to ionise $\frac{N o}{2}$ atoms of $X_{g} = \frac{N o}{2} \times I . E = E_{1}$ (given)