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Ideal Gas Equation

NO reacts wit...

Question

$N O$ reacts with $O_{2}$ to form $N O_{2}$ when $10 g$ of $N O_{2}$ is formed during the reaction, the mass of $O_{2}$ consumed is:

1.90 g

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5.0 g

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3.48 g

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13.9 g

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Solution

The correct option is D $3.48 g$
$N O + \frac{1}{2} O_{2} ⟶ N O_{2}$

By stiochiometry, $0.5$ moles of $O_{2}$ is consumed to form $1$ mole of $N O_{2}$

Moles of $N O_{2}$ formed= $\frac{10}{46} = 0.217$ moles
$∴$ Moles of $O_{2}$ consumed= $0.5 \times 0.217$
= $0.1087$ moles
$∴$ Mass of $O_{2}$ consumed= $0.1087 \times 32$
= $3.48 g$

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