Question

# Not counting geometrical isomers. How many isomers can C4H8 have?

A

5

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B

3

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C

4

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D

Data insufficient

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Solution

## The correct option is A 5 For the formula C4H8, Degree of unsaturation = (no of carbon atoms) +1-{No 8 H atoms +No halogens-No of nitrogen atoms} Whenever we encounter sulphur or oxygen we discount them. Degree of unsaturation is defined as the minimum no of bonds that must be broken to convert the given compound into a saturated open chain compound. For C2H4, D.U=1 In CH2=CH2, if we break the double bond (π bond) we get CH2=CH2+H2 (r)CH3-CH3 It may also be defined as the no of hydrogen molecules that need to be added to the given compound to make it an aliphatic alkane. D.U=no of π bonds+ no of cyclical structures in the compound For C4H8, degree for unsaturation =4+1-82=1 So C4H8 has on π bond OR one cyclical structure. So possible structures are: , , CH3-CH=CH-CH3 Ans=5 or a

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