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Question

Now can you simplify these?

(i) (x + 4) + (x − 2)

(ii) (2x + 3) + (x − 1)

(iii) (x + 1) + (x − 1)

(iv) (5x + 6y) + (2x − 3y)

(v) (x + y) + (x y)

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Solution

(i) (x + 4) + (x 2)

= (x + 4 + x) 2 [for any three numbers x, y, z, with y > z, x + (y z) = (x + y) z]

= (2x + 4) 2

= 2x + (4 − 2)

= 2x + 2

= 2(x + 1)

(ii) (2x + 3) + (x 1)

= (2x + 3 + x) 1 [for any three numbers x, y, z, with y > z, x + (y z) = (x + y) z]

= (3x + 3) 1

= 3x + (3 − 1)

= 3x + 2

(iii) (x + 1) + (x 1)

= (x + 1 + x) 1 [for any three numbers x, y, z, with y > z, x + (y z) = (x + y) z]

= (2x + 1) 1

= 2x + (1 − 1)

= 2x + 0

= 2x

(iv) (5x + 6y) + (2x 3y)

= (5x + 6y + 2x) 3y [for any three numbers x, y, z, with y > z, x + (y z) = (x + y) z]

= (7x + 6y) 3y

= 7x + (6y − 3y)

= 7x + 3y

(v) (x + y) + (x y)

= (x + y + x) y [for any numbers x, y, z, with y > z, x + (y z) = (x + y) z]

= (2x + y) y

= 2x + (yy)

= 2x + 0

= 2x


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