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Question

Now can’t you do these?

(i) −4 + (−1)

(ii) −6 + (−4)

(iii) −12 + (−8)

(iv) −8 + (−10)

(v)

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Solution

We know that for any two positive numbers x, y, we have x y = (x + y)

(i) 4 + (1) = 4 1

= − (4 + 1)

= 5

(ii) 6 + (4) = 6 4

= − (6 + 4)

= 10

(iii) 12 + (8) = 12 8

= − (12 + 8)

= 20

(iv) 8 + (10) = 8 10

= − (8 + 10)

= 18

(v)


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