Now do these also-i 3-1ii 5-4iii 12-2iv 8-9 v 9-12vi 4-5-1-5

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Standard VII

Mathematics

Addition and Subtraction of Integers

Now do these ...

Question

Now do these also:

(i) 3 + (−1)

(ii) 5 + (−4)

(iii)12 + (−2)

(iv) 8 + (−9)

(v) 9 + (−12)

(vi)

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Solution

(i) 3 + (−1) = −1 + 3 = 3 − 1 = 2

(ii) 5 + (−4) = −4 + 5 = 5 − 4 = 1

(iii) 12 + (−2) = −2 + 12 = 12 − 2 = 10

(iv) 8 + (−9) = −9 + 8 = 8 − 9 = −1

(v) 9 + (− 12) = −12 + 9 = 9 − 12 = −3

(vi)

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Similar questions

Now can’t you do these?

(i) −4 + (−1)

(ii) −6 + (−4)

(iii) −12 + (−8)

(iv) −8 + (−10)

(v)

Now compute these.

(i) $- 4 + 1$

(ii) $- 5 + 3$

(iii) $- 9 + 2$

(iv) $- 12 + 8$

(v) $- 14 + 1$

(vi) $- \frac{3}{4} + \frac{1}{4}$

Now can’t you do these?

(i) −4 + 7

(ii) −3 + 8

(iii) −6 + 9

(iv) −2 + 10

(v) −4 + 12

(vi)

Evaluate : $(i) \frac{5}{9} + \frac{- 7}{6} (i i) 4 + \frac{3}{- 5} (i i i) \frac{1}{- 15} + \frac{5}{- 12} (i v) \frac{5}{9} + \frac{3}{- 4} (v) \frac{- 8}{9} + \frac{- 5}{12} (v i) 0 + \frac{- 2}{7} (v i i) \frac{5}{- 11} + 0 (v i i i) 2 + \frac{- 3}{5} (i x) \frac{4}{- 9} + 1$

Now can’t you compute these?

(i) −4 − (−5)

(ii) −6 − (−9)

(iii) −12 − (−10)

(iv) −8 − (−7)

(v)

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Now do these also: (i) 3 + (−1) (ii) 5 + (−4) (iii)12 + (−2) (iv) 8 + (−9) (v) 9 + (−12) (vi)

(i) 3 + (−1) = −1 + 3 = 3 − 1 = 2 (ii) 5 + (−4) = −4 + 5 = 5 − 4 = 1 (iii) 12 + (−2) = −2 + 12 = 12 − 2 = 10 (iv) 8 + (−9) = −9 + 8 = 8 − 9 = −1 (v) 9 + (− 12) = −12 + 9 = 9 − 12 = −3 (vi)

Now do these also:

(i) 3 + (−1)

(ii) 5 + (−4)

(iii)12 + (−2)

(iv) 8 + (−9)

(v) 9 + (−12)

(vi)

(i) 3 + (−1) = −1 + 3 = 3 − 1 = 2

(ii) 5 + (−4) = −4 + 5 = 5 − 4 = 1

(iii) 12 + (−2) = −2 + 12 = 12 − 2 = 10

(iv) 8 + (−9) = −9 + 8 = 8 − 9 = −1

(v) 9 + (− 12) = −12 + 9 = 9 − 12 = −3

(vi)