Now compute these-i -4-1ii -5-3iii -9-2iv -12-8v -14-1vi -3-4-1-4

(i) −4 + 1 = 1 − 4 = −3 (ii) −5 + 3 = 3 − 5 = −2 (iii) −9 + 2 = 2 − 9 = −7 (iv) −12 + 8 = 8 − 12 = −4 (v) −14 + 1 = 1 − 14 = −13 (vi) ...

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Byju's Answer

Standard VII

Mathematics

Multiplication of Integers

Now compute t...

Question

Now compute these.
(i) $- 4 + 1$
(ii) $- 5 + 3$
(iii) $- 9 + 2$
(iv) $- 12 + 8$
(v) $- 14 + 1$
(vi) $- \frac{3}{4} + \frac{1}{4}$

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Solution

(i) $- 4 + 1 = 1 - 4 = - 3$ [Using commutative property, $a + b = b + a$ ]
(ii) $- 5 + 3 = 3 - 5 = - 2$
(iii) $- 9 + 2 = 2 - 9 = - 7$
(iv) $- 12 + 8 = 8 - 12 = - 4$
(v) $- 14 + 1 = 1 - 14 = - 13$
(vi) $- \frac{3}{4} + \frac{1}{4} = \frac{1}{4} - \frac{3}{4} = \frac{1 - 3}{4} = - \frac{1}{2}$

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Similar questions

Now do these also:

(i) 3 + (−1)

(ii) 5 + (−4)

(iii)12 + (−2)

(iv) 8 + (−9)

(v) 9 + (−12)

(vi)

Now can’t you compute these?

(i) −4 − (−5)

(ii) −6 − (−9)

(iii) −12 − (−10)

(iv) −8 − (−7)

(v)

Q. Find the value of each of the following:
(i)

{(\frac{1}{2})}^{- 1} + {(\frac{1}{3})}^{- 1} + {(\frac{1}{4})}^{- 1}

(ii)

{(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}

(iii) (2⁻¹ × 4⁻¹) ÷ 2⁻²
(iv) (5⁻¹ × 2⁻¹) ÷ 6⁻¹

Now can’t you do these?

(i) −4 + (−1)

(ii) −6 + (−4)

(iii) −12 + (−8)

(iv) −8 + (−10)

(v)

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

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Now compute these.(i) −4+1(ii) −5+3(iii) −9+2(iv) −12+8(v) −14+1(vi) −34+14

(i) −4+1=1−4=−3 [Using commutative property, a+b=b+a](ii) −5+3=3−5=−2(iii) −9+2=2−9=−7(iv) −12+8=8−12=−4(v) −14+1=1−14=−13(vi) −34+14=14−34=1−34=−12

Now compute these.
(i) $- 4 + 1$
(ii) $- 5 + 3$
(iii) $- 9 + 2$
(iv) $- 12 + 8$
(v) $- 14 + 1$
(vi) $- \frac{3}{4} + \frac{1}{4}$

(i) $- 4 + 1 = 1 - 4 = - 3$ [Using commutative property, $a + b = b + a$ ]
(ii) $- 5 + 3 = 3 - 5 = - 2$
(iii) $- 9 + 2 = 2 - 9 = - 7$
(iv) $- 12 + 8 = 8 - 12 = - 4$
(v) $- 14 + 1 = 1 - 14 = - 13$
(vi) $- \frac{3}{4} + \frac{1}{4} = \frac{1}{4} - \frac{3}{4} = \frac{1 - 3}{4} = - \frac{1}{2}$