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Question

Now do these also:

(i) 3 + (−1)

(ii) 5 + (−4)

(iii)12 + (−2)

(iv) 8 + (−9)

(v) 9 + (−12)

(vi)

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Solution

(i) 3 + (1) = −1 + 3 = 3 − 1 = 2

(ii) 5 + (4) = −4 + 5 = 5 − 4 = 1

(iii) 12 + (2) = −2 + 12 = 12 − 2 = 10

(iv) 8 + (9) = −9 + 8 = 8 − 9 = 1

(v) 9 + ( 12) = −12 + 9 = 9 − 12 = 3

(vi)


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