Question

Number of $\alpha$ and $\beta$ particles emitted when uranium nucleus ${}_{92}{U}^{238}$ decays to ${}_{82}P{b}^{214}$ are

• A. $6–\alpha particlesand2–\beta particles$
• B. $4–\alpha particlesand2–\beta particles$
• C. $2–\alpha particlesand6–\beta particles$
• D. $2–\alpha particlesand4–\beta particles$

Answer 1

The correct option is A $6–\alpha particlesand2–\beta particles$

${}_{92}{U}^{238}{\to }_{82}P{b}^{214}+6_{2}H{e}^4+2e^{-1}$
So $6\alpha$ and $2\beta$ are possible