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Line Spectra

Number of α...

Question

Number of $α$ -particles emitted during the emission is:
$_{92}^{238} U ⟶_{82}^{206} Pb + a_{2}^{4} He + b_{- 1}^{0} e$

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Solution

Number of $α$ -particles emitted during the emission is:
$_{92}^{238} U ⟶_{82}^{206} Pb + a_{2}^{4} He + b_{- 1}^{0} e$ is 8.

No. of $α$ -particles emitted $= \frac{238 - 206}{4} = \frac{32}{4} = 8$ .

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