Question

Number of angles of ${109}^o{28}^{\prime }$ is present in ${CCl}_4$ ?

• A. $2$
• B. $4$
• C. $6$
• D. $8$

Answer 1

The correct option is C $6$

Solution:- (C) 6

Let the 4 Cl atoms linked with carbon atom in $C{Cl}_4$ be 1, 2, 3 and 4 respectively.

$\therefore$ There will be 6 bond angles of $109°{28}^{\prime }$ in $C{Cl}_4$.

$\angle 1C2=\angle 1C3=\angle 1C4=\angle 2C3=\angle 2C4=\angle 3C4=109°{28}^{\prime }$