Question

Number of divisors of the form (4n + 2), n ≥ 0 of the integer 240 is ?

• A. 4
• B. 8
• C. 10
• D. 3

Answer 1

The correct option is A 4

Since, $240=2^4.3.5$
$\therefore$ Total number of divisors = (4 + 1)(2)(2) = 20 out of these 2, 6, 10, and 30 are of the form 4n + 2. Therefore, (a) is the answer .