Number of five digit natural numbers, with sum of digits equal to 43 are
A
15
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B
10
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C
35
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D
5
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Solution
The correct option is A15 Case-1 : Digits will be 9,9,9,9,7 natural number formed Hence the required permutation will be 5!4! Case-2 : Digits will be 9,9,9,8,8 natural number formed =5!3!.2! =5C2 =5×42 =10 Hence the required permutation will be 10+5=15