Question

Number of g-atoms of Sulphur present in $80.25$ gm of sulphur is:

(Atomic weight of S = 32)

• A. 32
• B. 5
• C. 10
• D. 2.5

Answer 1

The correct option is D 2.5

No. of g-atoms $=\frac{Weight}{AtomicWeight}$
On applying above concept:
No. of atoms of sulphur $=\frac{80.25}{32}=2.5$