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Question

Number of integral value(s) of k for which the equation 4x216x+k=0 has one root lie between 1 and 2 and other root lies between 2 and 3, is

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Solution

f(x)=4x216x+k=0
One root between 1 & 2
other root between 2 & 3.
According to rolle's theorem.
f(1).b(2)<0
(12+K)(16+K)<0
(k12)(K16)<0
Kϵ(12,16)
Also, f(2)b(3)<0
16+K(12+K)<0
(K16)(K12)<0
Kϵ(12,16)
Intersection both is Kϵ(12,16)
Total integral values possible of K=3{13,14,15}

1065169_1116948_ans_3253b008b2a5440285397b0ddadb9387.png

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