Number of lone pairs of electrons on $X$ e atoms $X e F_{2}, X e F_{4}$ and $X e F_{6}$ molecules are respectively.

3, 2 and 1

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4, 3 and 2

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2, 3 and 1

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3, 2 and 0

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Solution

The correct option is A 3, 2 and 1
$X e F_{2} = 2 + \frac{8 - 2}{2} = 2 + 3$
$b o n d p a i r l o n e p a i r$

$X e F_{4} = 4 + \frac{8 - 4}{2} = 4 + 2$
$b o n d p a i r l o n e p a i r$

$X e F_{6} = 6 + \frac{8 - 6}{2} = 6 + 1$
$b o n d p a i r l o n e p a i r$

Option A is correct.

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