Number of ordered triplets of natural number (a, b, c) for which $a b c \leq 11$ is

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Solution

The correct option is D 56
abc = 1 in 1 ways
abc = 2, 3, 5, 7, 11 in 15 ways
abc = 4, 9 in 12 ways
abc = 8 in 10 ways
abc = 6, 10 in 18 ways
So, total number of solution is 56

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