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Question
Number of products and number of fractions are respectively:
Ph−C|CH3H−CH2−CH3Cl2−−→hvproductsFractional−−−−−−−→DistillationFractions.
Number of products and number of fractions are respectively:
Ph−C|CH3H−CH2−CH3Cl2−−→hvproductsFractional−−−−−−−→DistillationFractions.
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Solution
The correct option is B 6,4
Ph−CHCH3−CH2−CH3Cl2−−→hvi)Ph−ClC∗−CH3−CH2CH3 (2 products)∗= chiral center ii)Ph−CHCH2Cl−CH2−CH3 (1 product)iii)Ph−CHCH3−CH∗Cl−CH3 (2 products)iv)Ph−CHCH3−CH2−CH2Cl (1 product)∴ Total 6 products and after fractional distillation 4 fractions are obtained.
Ph−CHCH3−CH2−CH3Cl2−−→hvi)Ph−ClC∗−CH3−CH2CH3 (2 products)
∗= chiral center
ii)Ph−CHCH2Cl−CH2−CH3 (1 product)
iii)Ph−CHCH3−CH∗Cl−CH3 (2 products)
iv)Ph−CHCH3−CH2−CH2Cl (1 product)
∴ Total 6 products and after fractional distillation 4 fractions are obtained.
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