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Byju's Answer
Standard XII
Mathematics
Inverse of a Function
Number of rea...
Question
Number of real solution of the equation
x
3
+
3
x
2
−
(
x
−
6
)
1
3
+
8
+
3
x
=
0
is
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Solution
(
x
+
1
)
3
=
(
x
−
6
)
1
3
−
7
(
x
+
1
)
3
+
6
=
(
x
−
6
)
1
3
−
1
f
(
x
)
f
−
1
(
x
)
So solution is f(x) = x
x
3
+
3
x
2
+
3
x
+
7
=
x
x
3
+
3
x
2
+
2
x
+
7
=
0
(
x
+
1
)
3
=
x
−
6
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0
Similar questions
Q.
The polynomial which when divided by −x
2
+ x − 1 gives a quotient x − 2 and remainder 3, is
(a) x
3
− 3x
2
+ 3x − 5
(b) −x
3
− 3x
2
− 3x − 5
(c) −x
3
+ 3x
2
− 3x + 5
(d) x
3
− 3x
2
− 3x + 5