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Question

Number of real solution of the equation x3+3x2(x6)13+8+3x=0 is

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Solution

(x+1)3=(x6)137
(x+1)3+6=(x6)131f(x)f1(x)
So solution is f(x) = x
x3+3x2+3x+7=x
x3+3x2+2x+7=0
(x+1)3=x6

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