Question

Number of sodium atom present in $8\text{g}$ of sodium is $X\times {10}^{23}$, then the value of $X$ is:
[Take $N_A=6\times {10}^{23}$]

• A. $2.08$
• B. $0.8$
• C. $4.08$
• D. $3.80$

Answer 1

The correct option is A $2.08$

$\text{Number of moles of sodium}=\frac{8}{23}$
$\text{Number of sodium atom}=\frac{8}{23}\times 6\times {10}^{23}$
$=2.08\times {10}^{23}$
Hence, $X=2.08$