Number of transformed equations of $x^{4} + 2 x^{3} - 12 x^{2} + 2 x - 1 = 0$ by eliminating third term is:

0

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1

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2

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3

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Solution

The correct option is C $2$
As we know for transformation $y = x + h$
$h$ can be obtained by differentiation .
Since we have to remove $x^{2}$ , so we have differentiate twice .
So, differentiating $x^{4} + 2 x^{3} - 12 x^{2} + 2 x - 1 = 0$
$12 h^{2} + 12 h - 24 = 0$
Solving this we get $2$ values for $h$ .

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