Number of unpaired electrons present in $[M n (C N)_{6}]^{3 -}$ is:

Zero

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Solution

The correct option is B 2

Number of d-electrons present in $[M n (C N)_{6}]^{3 -}$ is 4.

$C N^{-}$ is a strong field ligand hence pairing in $t_{2 g}$ orbitals with occur. It is inner orbital complex

Number of unpaired electrons = 2

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