The number of unpaired electrons present in Fe $^{+ 3}$ is :

5

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4

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3

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6

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Solution

The correct option is A $5$
The atomic number of $F e$ is $26$ and its electronic configuration is $[A r] 4 s^{2} 3 d^{6}$ .
Thus, the electronic configuration of $F e^{3 +}$ is $[A r] 3 d^{5}$ .
Hence, it has $5$ unpaired electrons in the d subshell.

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