Number of ways we can divide nine students into three teams containing four, three and two students is _______

1260

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1560

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1350

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1460

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Solution

The correct option is A 1260
option (a)

Since, no two teams are of same size;

The required number of ways $= \frac{9!}{4! 3! 2!} = 1260$

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Number of ways we can divide nine students into three teams containing four, three and two students is _______

The correct option is A 1260option (a) Since, no two teams are of same size; The required number of ways=9!4!3!2!=1260

The correct option is A 1260
option (a)

Since, no two teams are of same size;

The required number of ways $= \frac{9!}{4! 3! 2!} = 1260$