$O_{3}, N_{2} O, N O_{2}, S O_{2}, C O_{2}, S n C l_{2}, C l_{2} O, H C N, + N O_{2}$
Among the following if the number of linear molecules are $x$ and the number of angular molecules are $y$ . Then the value of $\frac{x}{y}$ would be

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Solution

We know generally linear molecules have $s p$ hybridisation.

$In O_{3} the central O atom is s p^{2} hybridised$ and it is angular in shape.
$In N_{2} O the central N atom is s p hybridised$ and linear in shape.
$In N O_{2} the central N atom is s p^{2} hybridised$ and angular in shape.
$In S O_{2} the central S atom is s p^{2} hybridised$ and angular in shape.
$In C O_{2} the central C atom is s p hybridised$ and linear in shape.
$In S n C l_{2} the central Sn atom is s p^{2} hybridised$ with one lone pair and hence, angular in shape.
$In C l_{2} O the central O atom is s p^{3} hybridised$ with two lone pair and angular in shape.
$In H C N the central atom C is sp hybridised and linear in shape$
$In + N O_{2} the central atom + N is sp hybridised and linear in shape$
Hence $y = 5, x = 4$
Hence, x = 4 and y = 5 so $\frac{x}{y} = \frac{4}{5} = 0.8$

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