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Question

O is the centre of the circle with radius 5 cm . Chords AB and CD are parallel. AB=6 cm and CD=8 cm. If PQ is distance between AB and CD, then PQ is equal to
242754_27cace9fcbce4ea1baef2675c1bae31f.png

A
10 cm
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B
8 cm
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C
7 cm
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D
72 cm
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Solution

The correct option is A 7 cm
GivenOisthecentreofacircleofradius5cm.AB=6cm&CD=8cmareparallelchordswhoareatperpendiculardistanceofPQ.TofindoutPQ=?SolutionWejoinOCanddropperpendicularsOM&ONfromOtoAB&CD.OM&ONmeetAB&CDatM&Nrespectively.M&NaremidpointsofAB&CDrespectivelysincetheperpendicular,droppedfromthecenterofacircletoanyofitschordbisectsthelatter.SoAM=12×AB=12×6cm=3cmandCN=12×CD=12×8cm=4cm.NowOMAB&ONCD.OMA=90o=ONC.i.eΔOMA&ΔONCarerighttriangleswithOA&OCashypotenusesrespectively.So,byPythagorastheorem,wehaveOM=OA2AM2=5232cm=4cmandON=OC2CN2=5242cm=3cm.MN=OM+ON=(4+3)cm=7cm.NowABCDandPQistheperpendiculardistancebetweenthem.AlsoOM&ONareonthesamestraightlineasbothofthemareperpediculartoapairofstraightlinesAB&CDandtheypassthroughthesamepointO.SoMNistheperpendiculardistancebetweenAB&CD.PQ=MN=7cm.AnsOptionC.
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