Question

# Observe the following listsList - IList - IIA) minimum value of |x−5| is 1) -1B) minimum value of |x−3|+|x−7| is2) 0C) maximum value of |sin5x|3) √2D) maximum value of |sin+cosx|4) 15) 4

A
A - 2, B - 5, C - 3, D - 2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
A - 2, B - 5, C - 4, D - 3.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
A - 2, B - 3, C - 1, D - 4.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A - 2, B - 3, C - 5, D - 1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is D A - 2, B - 5, C - 4, D - 3.A)∣x−5∣≥0 So the minimum value of |x−5| is 0B)∣x−3∣+∣x−7∣ The minimum value will be at x=7+32=5 So the minimum value of ∣x−3∣+∣x−7∣ is |5−3|+|5−7|=2+2=4C)sin5x∈[−1,1]⟹|sin5x|∈[0,1] So the maximum value is 1D)sinx+cosx∈[−√2,√2]⟹∣sinx+cosx∣∈[0,√2] So the maximum value is √2

Suggest Corrections
0
Related Videos
Solving Trigonometric Equations
MATHEMATICS
Watch in App