obtain an equation for the SHM of a particle whose amplitude is 0.05 m and frequency 25 hz.The initial phase is (pie)/3

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Solution

: ω = 2πn = 2π × 25 = 50π
The equation of SHM is y = a sin (ω t + φο)
The displacement equation of SHM is : y = 0.05 sin (50πt + π/3)

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obtain an equation for the SHM of a particle whose amplitude is 0.05 m and frequency 25 hz.The initial phase is (pie)/3

: ω = 2πn = 2π × 25 = 50π The equation of SHM is y = a sin (ω t + φο) The displacement equation of SHM is : y = 0.05 sin (50πt + π/3)

: ω = 2πn = 2π × 25 = 50π
The equation of SHM is y = a sin (ω t + φο)
The displacement equation of SHM is : y = 0.05 sin (50πt + π/3)