Obtain simple logical expression for the following.
$p \lor (q \land \sim q)$

p \land (q \land \sim q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sim q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sim p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $p$
p q $\sim p$ $q \land \sim q$ $p \lor (q \land \sim q)$
T T F F T
T F T F T
F T F F F
F F T F F
We can solve this problem by using truth table.
$∴ p \lor (\sim q \land \sim q) \equiv p$

Suggest Corrections

Similar questions

[p \land (q \land r)] \lor [\sim r \lor \sim q \land p]

[p \lor (\sim p \land q)] \lor [(\sim q \land r) \land \sim p]

(p \land r \lor q) \lor [\sim p \lor (q \land \sim r)]

P \lor \sim Q

\sim (\sim P \land Q)

(P \land Q) \lor (P \land \sim Q) \lor (\sim P \land \sim Q)

(P \land Q) \lor (P \land \sim Q) \lor (\sim P \land Q)

p

q,

\sim (p \lor q) \lor (\sim p \land q)

Join BYJU'S Learning Program