Question

Obtain the parametric equation of the following circle.
$2x^2+2y^2=7$

Answer 1

$2x^2+2y^2=7$

$2(x^2+y^2)=7$

$x^2+y^2=\frac{7}{2}={\left(\sqrt{\frac{7}{2}}\right)}^2$

$x=\sqrt{\frac{7}{2}}\cos \theta ,y=\sqrt{\frac{7}{2}}\sin \theta$