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Question

# Odds 8 to 5 against a person who is 40 years old living till he is 70 and 4 to 3 against another person now 50 till he will be living 80. Probability that one of them will be alive next 30 years.

A
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B
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C
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D
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Solution

## The correct option is B Probability [Person A will die in 30 years] = 88+5 P(A) = 813⇒ P(¯¯¯¯A)=513 Similarly, P(B) = 47 ⇒ P(¯¯¯¯B)=37 Therefore are two ways in which one person is alive after 30 years. ¯¯¯¯AB and A¯¯¯¯B and event are independent. So, required probability =P(¯¯¯¯A).P(B)+P(A).P(¯¯¯¯B)=513×47+813×37=4491

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