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Question

# Odds 8 to 5 against a person who is 40yr old living till he is 70 and 4 to 3 against another person now 50 till he will be living 80. Probability that one of them will be alive next 30yr.

A
5991
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B
4491
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C
5191
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D
3291
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Solution

## The correct option is B 4491let A be the event that person A will die in 30 yrs and let B be the event that person B will die in 30 yrs.P(A)=88+5P(A)=813⇒P(¯A)=513Similarly, P(B)=47 or P(¯B)=37There are two ways in which one person is alive after 30 yr. ¯AB and A¯B and event are independent.So, required probability=P(¯A)⋅P(B)+P(A)⋅P(¯B)=513⋅47+813⋅37=4491.

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