Of all chords which passes through a given point inside the circle the shortest chord will always be the one with the given point as its midpoint
True
The shortest chord among a set of chords passing through a given point P would be the one which has its midpoint at P. Here in this case its CD since its given as
CP = PD.
Proof
Consider any other chord passing through P which doesn't have its midpoint at P, say XY .Let the length of CD, the chord with P as midpoint as l and d as the perpendicular length from O to CD.
Now draw a perpendicular from O to the chord XY, OQ
If you consider △OPQ we get that its right angled at Q, with OP as hypotenuse and OQ as altitude.
This shows that OQ < OP
OQ< P
So the shortest distance from centre to XY is less than shortest distance from centre to CD.
⇒ length of XY >length of CD
⇒ CD is the shortest chord possible