Of the following acids, the one that is strongest is :

H B r O_{4}

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H O C l

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H {N O}_{2}

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H_{3} {P O}_{3}

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Solution

The correct option is D $H B r O_{4}$
As oxidation state of central atom increases, acidity increases.
So, strongest acid is that which has maximum value of oxidation number (O.N) of the central atom.
$H B r O_{4}$ ; O.N of $B r = + 7$ (strongest acid)
$H O C l$ ; O.N of $C l = + 1$
$H {N O}_{2}$ ; O.N of $N = + 3$
$H_{3} {P O}_{3}$ ; O.N of $P = + 3$

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H_{3} {P O}_{4}, H_{2} {S O}_{4}, H_{3} {P O}_{3}, H_{2} {C O}_{3}, H_{2} S_{2} O_{7}, H_{3} B O_{3}, H_{3} {P O}_{2}, H_{2} {C r O}_{4}, H_{2} {S O}_{3}

H_{3} {P O}_{3}

H_{3} {P O}_{3}

- 106.68 k J / m o l

N a O H

H C l

N a O H

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Δ H_{i o n i z a t i o n}

H_{3} {P O}_{3}

H_{3} {P O}_{4}, H_{3} {P O}_{2}

H_{3} {P O}_{3}

H_{3} {P O}_{4}, H_{3} {P O}_{3}, H_{3} {P O}_{2}

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